Question: Slope of the Line:
top-right: a blue diagonal line on the coordinate plane rises from about $(-2, -10)$ to about $(10, 0)$, so the slope is $\frac{5}{6}$.
1. **State the problem:** Find the slope of the line passing through the points $(-2, -10)$ and $(10, 0)$.
2. **Formula for slope:** The slope $m$ of a line through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
3. **Substitute the points:**
$$m = \frac{0 - (-10)}{10 - (-2)} = \frac{0 + 10}{10 + 2} = \frac{10}{12}$$
4. **Simplify the fraction:**
$$m = \frac{\cancel{10}}{\cancel{12}} = \frac{5}{6}$$
5. **Interpretation:** The slope of the line is $\frac{5}{6}$, which means for every 6 units moved horizontally to the right, the line rises 5 units vertically.
**Final answer:** The slope of the line is $\frac{5}{6}$.