Question: Given the equation $y = -2x + 5$:
a) Complete the table of values.
x y
-1
0
3
b) Graph the equation.
Graph shape: a straight line with equation $y = -2x + 5$, passing through the points $(-1, 7)$, $(0, 5)$, and $(3, -1)$, position_hint = center
1. **State the problem:** We are given the linear equation $$y = -2x + 5$$ and asked to complete a table of values for $x = -1, 0, 3$ and then graph the equation.
2. **Formula and rules:** The equation is in slope-intercept form $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept.
3. **Calculate $y$ for each $x$ value:**
- For $x = -1$:
$$y = -2(-1) + 5 = 2 + 5 = 7$$
- For $x = 0$:
$$y = -2(0) + 5 = 0 + 5 = 5$$
- For $x = 3$:
$$y = -2(3) + 5 = -6 + 5 = -1$$
4. **Complete the table:**
| $x$ | $y$ |
|-----|-----|
| -1 | 7 |
| 0 | 5 |
| 3 | -1 |
5. **Graph the equation:**
- The graph is a straight line passing through the points $(-1,7)$, $(0,5)$, and $(3,-1)$.
- The slope $m = -2$ means the line goes down 2 units for every 1 unit it moves to the right.
- The y-intercept $b = 5$ is where the line crosses the y-axis.
**Final answer:**
The completed table is:
| $x$ | $y$ |
|-----|-----|
| -1 | 7 |
| 0 | 5 |
| 3 | -1 |