Subjects algebra

Linear Equation 1915Cd

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Question: 4 + \frac{1}{2} x + 3 = 10
1. **State the problem:** Solve the equation $$4 + \frac{1}{2} x + 3 = 10$$ for $$x$$. 2. **Combine like terms:** Add the constants $$4$$ and $$3$$ on the left side. $$4 + 3 = 7$$ So the equation becomes: $$7 + \frac{1}{2} x = 10$$ 3. **Isolate the term with $$x$$:** Subtract $$7$$ from both sides. $$7 + \frac{1}{2} x - 7 = 10 - 7$$ $$\frac{1}{2} x = 3$$ 4. **Solve for $$x$$:** Multiply both sides by the reciprocal of $$\frac{1}{2}$$, which is $$2$$. $$2 \times \frac{1}{2} x = 2 \times 3$$ $$\cancel{2} \times \frac{1}{\cancel{2}} x = 6$$ $$x = 6$$ **Final answer:** $$x = 6$$