Subjects algebra

Linear Equation 306Cf7

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1. The problem is not explicitly stated, so I will assume you want a general example of solving a linear equation with solution steps. 2. Let's solve the equation: $$3x + 5 = 20$$ 3. The formula used here is to isolate the variable $x$ by performing inverse operations. 4. Step 1: Subtract 5 from both sides to get rid of the constant term on the left. $$3x + 5 - 5 = 20 - 5$$ $$3x = 15$$ 5. Step 2: Divide both sides by 3 to solve for $x$. $$\frac{3x}{3} = \frac{15}{3}$$ $$\cancel{3}x / \cancel{3} = 5$$ $$x = 5$$ 6. The solution is $x = 5$. This means when $x$ is 5, the original equation holds true.