Subjects algebra

Linear Expression F73A57

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Question: From $x + 2y = 2$, we can express $y$ in terms of $x$: $y = \frac{2 - x}{2}$. Since $x \geq 0$ and $y \geq 0$, the limits for $x$ are from $0$ to $2$. Elaborate
1. **State the problem:** We start with the linear equation $$x + 2y = 2$$ and want to express $y$ in terms of $x$. 2. **Isolate $y$:** To express $y$ in terms of $x$, subtract $x$ from both sides: $$x + 2y = 2 \implies 2y = 2 - x$$ 3. **Divide both sides by 2:** $$y = \frac{2 - x}{2}$$ 4. **Consider the domain restrictions:** Since $x \geq 0$ and $y \geq 0$, we find the valid range for $x$. 5. **Find $x$ limits from $y \geq 0$:** $$y = \frac{2 - x}{2} \geq 0 \implies 2 - x \geq 0 \implies x \leq 2$$ 6. **Combine with $x \geq 0$:** The domain for $x$ is $$0 \leq x \leq 2$$. 7. **Summary:** - The function is $$y = \frac{2 - x}{2}$$. - The domain is $$x \in [0, 2]$$. - Both $x$ and $y$ are non-negative in this interval. This means the line segment from $(0,1)$ to $(2,0)$ in the coordinate plane satisfies the equation and the given constraints.