Subjects algebra

Linear Inequality Fractions 99F319

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Question: Solve the following inequality: 1 > -3 \left( \frac{2}{3} x - 4 \right) - 1
1. **State the problem:** Solve the inequality $$1 > -3 \left( \frac{2}{3} x - 4 \right) - 1$$. 2. **Rewrite the inequality:** $$1 > -3 \left( \frac{2}{3} x - 4 \right) - 1$$ 3. **Add 1 to both sides to isolate the term with $x$:** $$1 + 1 > -3 \left( \frac{2}{3} x - 4 \right)$$ $$2 > -3 \left( \frac{2}{3} x - 4 \right)$$ 4. **Distribute $-3$ inside the parentheses:** $$2 > -3 \times \frac{2}{3} x + (-3) \times (-4)$$ $$2 > -2x + 12$$ 5. **Subtract 12 from both sides:** $$2 - 12 > -2x + 12 - 12$$ $$-10 > -2x$$ 6. **Divide both sides by $-2$ to solve for $x$.** Remember, dividing by a negative number reverses the inequality sign: $$\frac{-10}{\cancel{-2}} \; \cancel{>} \; \frac{-2x}{\cancel{-2}}$$ $$5 < x$$ 7. **Rewrite the solution:** $$x > 5$$ **Final answer:** $$x > 5$$