1. The problem is to evaluate $\ln\left(\frac{2}{1}\right)$.\n\n2. Recall the logarithm property: $\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)$.\n\n3. Applying this property, we get $\ln(2) - \ln(1)$.\n\n4. Since $\ln(1) = 0$, the expression simplifies to $\ln(2)$.\n\n5. Therefore, $\ln\left(\frac{2}{1}\right) = \ln(2)$.