1. **State the problem:** Write the expression $\log_5 \left(\frac{1}{2}\right) + \log_5 50$ as a single logarithm and evaluate it.
2. **Recall the logarithm property:** The sum of logarithms with the same base can be combined using the product rule:
$$\log_b A + \log_b B = \log_b (A \times B)$$
3. **Apply the product rule:**
$$\log_5 \left(\frac{1}{2}\right) + \log_5 50 = \log_5 \left(\frac{1}{2} \times 50\right)$$
4. **Simplify the argument:**
$$\frac{1}{2} \times 50 = 25$$
5. **Rewrite the expression:**
$$\log_5 25$$
6. **Evaluate the logarithm:** Since $25 = 5^2$,
$$\log_5 25 = \log_5 5^2 = 2$$
**Final answer:**
$$\boxed{2}$$
Logarithm Sum 949Ab7
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