Subjects algebra

Logarithm Sum Dcb6Fa

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Question: Evaluate the following expression using the properties of logarithms. log₅(5)+log₅(25)+log₅(625) ○ 7 ○ 3 ○ 25 ○ 15
1. **State the problem:** Evaluate $$\log_5(5) + \log_5(25) + \log_5(625)$$ using properties of logarithms. 2. **Recall the properties:** The logarithm of a product is the sum of the logarithms: $$\log_b(x) + \log_b(y) = \log_b(xy)$$. 3. **Apply the property:** Combine the terms: $$\log_5(5) + \log_5(25) + \log_5(625) = \log_5(5 \times 25 \times 625)$$ 4. **Calculate the product inside the log:** $$5 \times 25 = 125$$ $$125 \times 625 = 78125$$ So, $$\log_5(5 \times 25 \times 625) = \log_5(78125)$$ 5. **Express 78125 as a power of 5:** Since $$5^1 = 5$$, $$5^2 = 25$$, $$5^4 = 625$$, let's find the exponent for 78125. Note that $$78125 = 5^?$$ Calculate: $$5^7 = 5^{4+2+1} = 5^4 \times 5^2 \times 5^1 = 625 \times 25 \times 5 = 78125$$ 6. **Evaluate the logarithm:** $$\log_5(78125) = 7$$ **Final answer:** $$7$$