Subjects algebra

Mileage Comparison Bb6099

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Question: Two friends, Serenity and Julia, had just bought their first cars. The equation $y = 35.2x$ represents the number of miles, $y$, that Serenity can drive her car for every $x$ gallons of gas. The graph below represents the number of miles, $y$, that Julia can drive her car for every $x$ gallons of gas. Julia's Gas Mileage Miles Driven 900 850 800 750 700 650 600 550 500 450 400 350 300 250 200 150 100 50 0 0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 y x $(10,189)$ $(20,378)$ Gallons of Gas Use the dropdown menu and answer-blank below to form a true statement. Answer Attempt 1 out of 2 Serenity can travel ____ miles ____ than Julia on one gallon of gas.
1. **State the problem:** We want to compare how many miles Serenity and Julia can each drive on one gallon of gas. 2. **Serenity's mileage:** Given by the equation $$y = 35.2x$$, where $y$ is miles and $x$ is gallons. For one gallon, substitute $x=1$: $$y = 35.2 \times 1 = 35.2$$ miles. 3. **Julia's mileage:** From the graph, two points are given: $(10,189)$ and $(20,378)$. We find Julia's mileage per gallon by calculating the slope of the line connecting these points: $$\text{slope} = \frac{378 - 189}{20 - 10} = \frac{189}{10} = 18.9$$ miles per gallon. 4. **Compare mileages:** Serenity drives $35.2$ miles per gallon, Julia drives $18.9$ miles per gallon. 5. **Form a true statement:** Serenity can travel $35.2 - 18.9 = 16.3$ miles more than Julia on one gallon of gas. **Final answer:** Serenity can travel **16.3 miles more** than Julia on one gallon of gas.