Subjects algebra

Movie Costs 303Fbe

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Use the AI math solver

Question: 30 + .8x = 14 + 1.20x 20 = x + .4 x = 2x ten b. Solution. .089 3. Joycie has a VIP membership to a movie theater which costs $27 a year and $6.00 for each movie she sees. Claire doesnt have a membership, so she pays $8.25 for each movie she sees. How many movies would the two girls have to see in a year in order to pay the same amount? a. Equation __________________________ b. Solution __________________________ Graph shapes: a film reel icon is shown in the lower-left area; position_hint=bottom-left.User: Solve
1. **State the problem:** Joycie pays a yearly membership fee plus a cost per movie, while Claire pays only per movie. We want to find the number of movies $x$ where their total costs are equal. 2. **Define variables and write the equation:** Let $x$ be the number of movies seen in a year. Joycie's cost: $$27 + 6x$$ Claire's cost: $$8.25x$$ Set them equal to find $x$: $$27 + 6x = 8.25x$$ 3. **Solve the equation:** Subtract $6x$ from both sides: $$27 + \cancel{6x} = 8.25x - \cancel{6x}$$ $$27 = 2.25x$$ Divide both sides by $2.25$: $$\frac{27}{\cancel{2.25}} = \frac{2.25x}{\cancel{2.25}}$$ $$12 = x$$ 4. **Interpretation:** They must each see $12$ movies in a year to pay the same amount. **Final answer:** $$x = 12$$