Subjects algebra

Necklace Bracelet A07Bff

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1. **State the problem:** We need to find the price of a necklace and a bracelet given that together they cost 192 and the necklace costs 3 times as much as the bracelet. 2. **Define variables:** Let the price of the bracelet be $x$. 3. **Express the necklace price:** Since the necklace costs 3 times as much, its price is $3x$. 4. **Write the equation:** The total cost is the sum of the bracelet and necklace prices: $$x + 3x = 192$$ 5. **Simplify the equation:** $$4x = 192$$ 6. **Solve for $x$:** $$x = \frac{192}{4}$$ $$x = 48$$ 7. **Find the necklace price:** $$3x = 3 \times 48 = 144$$ 8. **Answer:** The bracelet costs 48 and the necklace costs 144.