Subjects algebra

Parabola Analysis 71D7C4

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Question: Worked Examples 1 Graph $y \geq x^2 - 2$ 2 Graph $y < x^2 + 2x - 3$ 3 Graph $x^2 + y \leq 16$ 4 Graph $y > -x^2 + 6$ 5 Graph $y \leq x^2 - 4x + 1$ y \geq x^2 + 4 y = -x^2 + 4 solid curve 1st point: $(0,0)$ y = -x^2 + 4 $0 = -(0)^2 + 4$ $0 \neq 4$ false Solve for the x-intercept $0 = x^2 + 4$ $x^2 = \pm \sqrt{4}$ $x = \pm 2$ $x_1 = 2$ $(2,0)$ $x_2 = -2$ $(-2,0)$ Find the vertex $V(h,k) = \left(-\frac{b}{2a}, \frac{4ac-b^2}{4a}\right)$ a = -1 b = 0 c = 4 = $(0,4)$ Graph shape: a downward-opening parabola with vertex at $(0,4)$, x-intercepts at $(-2,0)$ and $(2,0)$, and shaded regions outside the parabola. position_hint: center Solve the following using the solution provided
1. **State the problem:** We are asked to analyze and graph the parabola given by the inequality $y \geq x^2 + 4$ and the equation $y = -x^2 + 4$. We will find the vertex, x-intercepts, and describe the shading region. 2. **Find the x-intercepts of $y = -x^2 + 4$:** Set $y=0$ to find x-intercepts: $$0 = -x^2 + 4$$ Rearranged: $$x^2 = 4$$ Taking square roots: $$x = \pm 2$$ So the x-intercepts are at points $(2,0)$ and $(-2,0)$. 3. **Find the vertex of the parabola $y = -x^2 + 4$:** The vertex formula for a parabola $y = ax^2 + bx + c$ is: $$V\left(h,k\right) = \left(-\frac{b}{2a}, c - \frac{b^2}{4a}\right)$$ Here, $a = -1$, $b = 0$, and $c = 4$. Calculate $h$: $$h = -\frac{0}{2 \times -1} = 0$$ Calculate $k$: $$k = 4 - \frac{0^2}{4 \times -1} = 4$$ So the vertex is at $(0,4)$. 4. **Graph shape and shading:** Since $a = -1 < 0$, the parabola opens downward. The inequality $y \geq x^2 + 4$ describes the region above the parabola $y = x^2 + 4$, which opens upward with vertex at $(0,4)$. The parabola $y = -x^2 + 4$ opens downward with vertex at $(0,4)$ and x-intercepts at $(-2,0)$ and $(2,0)$. The shaded region for $y = -x^2 + 4$ is outside the parabola (above it), as described. 5. **Summary:** - Parabola $y = -x^2 + 4$ has vertex $(0,4)$ and x-intercepts $(-2,0)$ and $(2,0)$. - It opens downward. - The region outside the parabola is shaded. This completes the analysis and graphing of the given parabola and inequalities.