Question: What is the equation of the line that goes through $(-2, 1)$ and is parallel to $y= \frac{4}{3} x + 7$?
1. **State the problem:** Find the equation of the line passing through the point $(-2, 1)$ and parallel to the line $y= \frac{4}{3} x + 7$.
2. **Recall the formula for a line parallel to another:** Lines that are parallel have the same slope.
3. **Identify the slope of the given line:** The slope $m$ of the line $y= \frac{4}{3} x + 7$ is $\frac{4}{3}$.
4. **Use point-slope form:** The equation of a line with slope $m$ passing through point $(x_1, y_1)$ is
$$y - y_1 = m(x - x_1)$$
5. **Substitute the known values:** $m = \frac{4}{3}$, $x_1 = -2$, $y_1 = 1$
$$y - 1 = \frac{4}{3} (x - (-2))$$
which simplifies to
$$y - 1 = \frac{4}{3} (x + 2)$$
6. **Check the options:** The correct equation is
$$(y - 1) = \frac{4}{3} (x + 2)$$
**Final answer:** $(y - 1) = \frac{4}{3} (x + 2)$