Question: Find the slope of a line perpendicular to the line whose equation is $x - y = 3$. Fully simplify your answer.
1. **State the problem:** We need to find the slope of a line perpendicular to the line given by the equation $$x - y = 3$$.
2. **Rewrite the equation in slope-intercept form:** The slope-intercept form is $$y = mx + b$$, where $$m$$ is the slope.
Starting with $$x - y = 3$$:
$$-y = -x + 3$$
Multiply both sides by $$-1$$:
$$y = x - 3$$
3. **Identify the slope of the given line:** From $$y = x - 3$$, the slope $$m$$ is $$1$$.
4. **Find the slope of the perpendicular line:** The slope of a line perpendicular to another is the negative reciprocal of the original slope.
The negative reciprocal of $$1$$ is:
$$-\frac{1}{1} = -1$$
5. **Final answer:** The slope of the line perpendicular to the given line is $$\boxed{-1}$$.