Subjects algebra

Phone Plan Equality 2A1603

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Question: Customers of a phone company can choose between two service plans for long distance calls. The first plan has no monthly fee but charges $0.14 for each minute of calls. The second plan has a $21 monthly fee and charges an additional $0.10 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?
1. **State the problem:** We want to find the number of minutes $m$ for which the cost of the two plans is the same. 2. **Define variables and costs:** - Let $m$ be the number of minutes of calls. - Cost of Plan 1: $0.14m$ - Cost of Plan 2: $21 + 0.10m$ 3. **Set up the equation for equality:** $$0.14m = 21 + 0.10m$$ 4. **Solve for $m$:** Subtract $0.10m$ from both sides: $$0.14m - 0.10m = 21 + 0.10m - 0.10m$$ $$0.04m = 21$$ 5. **Isolate $m$ by dividing both sides by $0.04$:** $$m = \frac{21}{0.04}$$ Show cancellation: $$m = \frac{21}{\cancel{0.04}} \times \frac{\cancel{1}}{1}$$ 6. **Calculate the value:** $$m = 525$$ 7. **Interpretation:** The costs of the two plans are equal when the customer makes 525 minutes of calls.