Question: Find $f(-1)$ for the piece-wise function.
$f(x) = \begin{cases} 2x + 2, & x \leq 0 \\ -\frac{4}{3}x + 4, & x > 0 \end{cases}$
$f(-1) = [?]$
1. **State the problem:** We need to find the value of $f(-1)$ for the given piecewise function.
2. **Identify which piece to use:** Since $-1 \leq 0$, we use the first piece of the function:
$$f(x) = 2x + 2$$
3. **Substitute $x = -1$ into the first piece:**
$$f(-1) = 2(-1) + 2$$
4. **Calculate the value:**
$$f(-1) = -2 + 2$$
$$f(-1) = 0$$
5. **Final answer:**
$$\boxed{0}$$