Question: Expand:
$f(x) = x^3 - [blank]x^2 + [blank]x - [blank]$
1. **State the problem:** We need to expand the cubic polynomial $f(x) = x^3 - [blank]x^2 + [blank]x - [blank]$ by filling in the blanks with appropriate coefficients.
2. **General form of a cubic polynomial:** A cubic polynomial can be written as
$$f(x) = ax^3 + bx^2 + cx + d$$
where $a$, $b$, $c$, and $d$ are constants.
3. **Understanding the blanks:** The blanks represent unknown coefficients for the terms $x^2$, $x$, and the constant term.
4. **If the polynomial is given as a product of factors, for example:**
$$f(x) = (x - r_1)(x - r_2)(x - r_3)$$
we can expand it step-by-step:
5. **Step 1: Expand the first two factors:**
$$ (x - r_1)(x - r_2) = x^2 - (r_1 + r_2)x + r_1 r_2 $$
6. **Step 2: Multiply the result by the third factor:**
$$ (x^2 - (r_1 + r_2)x + r_1 r_2)(x - r_3) $$
7. **Step 3: Distribute:**
$$ x^3 - r_3 x^2 - (r_1 + r_2) x^2 + (r_1 + r_2) r_3 x + r_1 r_2 x - r_1 r_2 r_3 $$
8. **Step 4: Combine like terms:**
$$ x^3 - (r_1 + r_2 + r_3) x^2 + (r_1 r_2 + r_2 r_3 + r_1 r_3) x - r_1 r_2 r_3 $$
9. **Final expanded form:**
$$ f(x) = x^3 - (r_1 + r_2 + r_3) x^2 + (r_1 r_2 + r_2 r_3 + r_1 r_3) x - r_1 r_2 r_3 $$
This shows the coefficients for the blanks in terms of the roots $r_1$, $r_2$, and $r_3$.
**Summary:**
- The coefficient of $x^2$ is the negative sum of the roots.
- The coefficient of $x$ is the sum of the products of the roots taken two at a time.
- The constant term is the negative product of all three roots.
If you provide specific roots or factors, I can compute the exact coefficients for the blanks.