Question: Match the polynomial on the left with the appropriately factored expression on the right.
$x^2 - 36$
$x^2 - 12x + 36$
$(x - 9)(x - 4)$
$(x - 6)(x - 6)$
$(x - 6)(x + 6)$
$(x + 6)(x + 6)$
1. **State the problem:** We need to match each polynomial on the left with its correct factored form on the right.
2. **Recall factoring formulas:**
- Difference of squares: $$a^2 - b^2 = (a - b)(a + b)$$
- Perfect square trinomial: $$a^2 - 2ab + b^2 = (a - b)^2$$
3. **Match $x^2 - 36$:**
- Recognize $36 = 6^2$, so $x^2 - 36 = x^2 - 6^2$.
- Using difference of squares: $$x^2 - 6^2 = (x - 6)(x + 6)$$
4. **Match $x^2 - 12x + 36$:**
- Note $36 = 6^2$ and $-12x = -2 \times 6 \times x$.
- This fits perfect square trinomial: $$x^2 - 2 \times 6 \times x + 6^2 = (x - 6)^2 = (x - 6)(x - 6)$$
5. **Check remaining factored forms:**
- $(x - 9)(x - 4)$ expands to $x^2 - 13x + 36$, which does not match any polynomial on the left.
- $(x + 6)(x + 6)$ expands to $x^2 + 12x + 36$, which does not match any polynomial on the left.
**Final matches:**
- $x^2 - 36$ matches $(x - 6)(x + 6)$
- $x^2 - 12x + 36$ matches $(x - 6)(x - 6)$
**Answer:**
- $x^2 - 36 \leftrightarrow (x - 6)(x + 6)$
- $x^2 - 12x + 36 \leftrightarrow (x - 6)(x - 6)$