Question: User: $(x-4)\times(2x^2+3x-2)$
1. **State the problem:** Simplify the expression $$(x-4)\times(2x^2+3x-2)$$.
2. **Formula and rules:** Use the distributive property (also called FOIL for binomials) to multiply each term in the first polynomial by each term in the second polynomial.
3. **Multiply each term:**
$$x \times 2x^2 = 2x^3$$
$$x \times 3x = 3x^2$$
$$x \times (-2) = -2x$$
$$-4 \times 2x^2 = -8x^2$$
$$-4 \times 3x = -12x$$
$$-4 \times (-2) = 8$$
4. **Combine all terms:**
$$2x^3 + 3x^2 - 2x - 8x^2 - 12x + 8$$
5. **Group like terms:**
$$2x^3 + (3x^2 - 8x^2) + (-2x - 12x) + 8$$
6. **Simplify:**
$$2x^3 - 5x^2 - 14x + 8$$
**Final answer:**
$$2x^3 - 5x^2 - 14x + 8$$