Question: Given the polynomial $4x^2 - 3x - 7$, what is the remainder when the polynomial is divided by $x + 7$?
1. **State the problem:** We need to find the remainder when the polynomial $$4x^2 - 3x - 7$$ is divided by $$x + 7$$.
2. **Recall the Remainder Theorem:** The remainder when a polynomial $$f(x)$$ is divided by $$x - a$$ is $$f(a)$$.
3. **Rewrite divisor:** Here, the divisor is $$x + 7$$ which can be written as $$x - (-7)$$, so $$a = -7$$.
4. **Evaluate the polynomial at $$x = -7$$:**
$$
4(-7)^2 - 3(-7) - 7 = 4(49) + 21 - 7 = 196 + 21 - 7
$$
5. **Simplify:**
$$
196 + 21 - 7 = 210
$$
6. **Conclusion:** The remainder when $$4x^2 - 3x - 7$$ is divided by $$x + 7$$ is $$210$$.