Question: Write $56$ as a product of prime factors.
1. **State the problem:** We need to express the number $56$ as a product of its prime factors.
2. **Recall the prime factorization method:** Prime factorization means breaking down a number into the product of prime numbers only.
3. **Start dividing $56$ by the smallest prime number:**
- $56 \div 2 = 28$
4. **Continue dividing by $2$ as long as the quotient is even:**
- $28 \div 2 = 14$
- $14 \div 2 = 7$
5. **Now $7$ is a prime number, so we stop here.**
6. **Write the prime factors:**
- $56 = 2 \times 2 \times 2 \times 7$
7. **Express using exponents:**
- $56 = 2^{3} \times 7$
**Final answer:**
$$56 = 2^{3} \times 7$$