Subjects algebra

Proportional Relationship C06694

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Question: This table shows a proportional relationship between the number of cups of bananas and strawberries used for a smoothie. a.) Enter the number of cups of bananas used for 1 cup of strawberries. b.) Enter the constant of proportionality that relates the quantities $x$ and $y$. c.) Enter an equation that relates the quantities. Cups of Bananas ($x$) Cups Strawberries ($y$) 1 $\frac{2}{25}$ 5 $\frac{2}{5}$ 2 $\frac{18}{25}$ 13 $\frac{3}{5}$
1. **State the problem:** We have a proportional relationship between cups of bananas ($x$) and cups of strawberries ($y$) with given data points: - $x=1 \frac{2}{25} = \frac{27}{25}$ cups, $y=5 \frac{2}{5} = \frac{27}{5}$ cups - $x=2 \frac{18}{25} = \frac{68}{25}$ cups, $y=13 \frac{3}{5} = \frac{68}{5}$ cups 2. **Find the number of cups of bananas used for 1 cup of strawberries:** Since $y$ is strawberries and $x$ is bananas, for 1 cup of strawberries, find $x$ such that $y=1$. 3. **Find the constant of proportionality $k$:** The relationship is $y = kx$ or $x = \frac{y}{k}$. Using the first pair: $$k = \frac{y}{x} = \frac{\frac{27}{5}}{\frac{27}{25}} = \frac{27}{5} \times \frac{25}{27} = 5$$ 4. **Check with the second pair:** $$k = \frac{\frac{68}{5}}{\frac{68}{25}} = \frac{68}{5} \times \frac{25}{68} = 5$$ 5. **Interpretation:** The constant of proportionality $k=5$ means strawberries are 5 times the bananas. 6. **Find cups of bananas for 1 cup of strawberries:** Since $y = 5x$, then $$x = \frac{y}{5}$$ For $y=1$ cup strawberries: $$x = \frac{1}{5}$$ 7. **Write the equation relating $x$ and $y$:** $$y = 5x$$ **Final answers:** - a) Number of cups of bananas for 1 cup of strawberries is $\frac{1}{5}$. - b) Constant of proportionality $k = 5$. - c) Equation relating quantities: $$y = 5x$$