Question: Given the equation $3^2 + 8 = 3$, identify the coefficients $a$, $b$, and $c$ that would be used in the quadratic formula. Then, solve for $x$. Enter each answer as an integer.
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1. **State the problem:** We are given the equation $3^2 + 8 = 3$ and asked to identify coefficients $a$, $b$, and $c$ for the quadratic formula, then solve for $x$.
2. **Analyze the equation:** The equation $3^2 + 8 = 3$ simplifies to $9 + 8 = 3$, which is $17 = 3$, a false statement. This means the equation as given is not a quadratic equation in $x$.
3. **Assumption:** Likely, the original equation was misstated. A quadratic equation generally has the form $$ax^2 + bx + c = 0$$.
4. **Hypothesis:** If the intended equation was $3x^2 + 8 = 3$, then we can rewrite it as:
$$3x^2 + 8 = 3$$
Subtract 3 from both sides:
$$3x^2 + 8 - 3 = 0$$
$$3x^2 + 5 = 0$$
5. **Identify coefficients:** Comparing to $ax^2 + bx + c = 0$:
- $a = 3$
- $b = 0$ (no $x$ term)
- $c = 5$
6. **Use quadratic formula:**
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
Substitute values:
$$x = \frac{-0 \pm \sqrt{0^2 - 4 \times 3 \times 5}}{2 \times 3} = \frac{\pm \sqrt{-60}}{6}$$
7. **Simplify the discriminant:**
$$\sqrt{-60} = \sqrt{-1 \times 4 \times 15} = 2i\sqrt{15}$$
8. **Final solutions:**
$$x = \frac{\pm 2i\sqrt{15}}{6} = \pm \frac{i\sqrt{15}}{3}$$
9. **Answer:**
- $a = 3$
- $b = 0$
- $c = 5$
- $x_1 = -\frac{i\sqrt{15}}{3}$
- $x_2 = \frac{i\sqrt{15}}{3}$
Since the problem asks for integer answers for $x$, and the solutions are complex, there are no integer solutions for $x$.
**Summary:** The coefficients are $a=3$, $b=0$, $c=5$. The solutions for $x$ are complex and not integers.
**Note:** If the original equation is different, please clarify.