Question: find the value of the quadratic polynomial $7s^2 - 4s + 6$ if: 1. $s=0$, 2. $s=-3$, 3. $s=4$
1. **State the problem:**
We need to find the value of the quadratic polynomial $$7s^2 - 4s + 6$$ for three different values of $s$: $0$, $-3$, and $4$.
2. **Formula used:**
The polynomial is given by $$P(s) = 7s^2 - 4s + 6$$.
3. **Evaluate for $s=0$:**
$$P(0) = 7(0)^2 - 4(0) + 6 = 0 - 0 + 6 = 6$$
4. **Evaluate for $s=-3$:**
$$P(-3) = 7(-3)^2 - 4(-3) + 6 = 7(9) + 12 + 6 = 63 + 12 + 6 = 81$$
5. **Evaluate for $s=4$:**
$$P(4) = 7(4)^2 - 4(4) + 6 = 7(16) - 16 + 6 = 112 - 16 + 6 = 102$$
**Final answers:**
- For $s=0$, $P(0) = 6$
- For $s=-3$, $P(-3) = 81$
- For $s=4$, $P(4) = 102$