Subjects algebra

Quadratic Imaginary 2D1C1F

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Question: User: $x^2+3=0$
1. **State the problem:** Solve the quadratic equation $$x^2 + 3 = 0$$. 2. **Formula and rules:** To solve for $x$, isolate $x^2$ and then take the square root of both sides. Remember that the square root of a negative number involves imaginary numbers. 3. **Isolate $x^2$:** $$x^2 = -3$$ 4. **Take the square root of both sides:** $$x = \pm \sqrt{-3}$$ 5. **Simplify the square root of a negative number:** $$x = \pm \sqrt{-1 \times 3} = \pm \sqrt{-1} \times \sqrt{3} = \pm i\sqrt{3}$$ 6. **Final answer:** $$x = \pm i\sqrt{3}$$ This means the solutions are purely imaginary numbers.