Subjects algebra

Radical Expressions A98B6F

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Question: 1 Simplify 7\sqrt{11} \times 3\sqrt{11} 2 Expand and simplify (\sqrt{2} + 2)(\sqrt{2} + 5) 3 Rationalise the denominator \frac{70}{\sqrt{10}} 4 Simplify 10\sqrt{7} + \sqrt{112}
1. **Simplify** $7\sqrt{11} \times 3\sqrt{11}$. The problem asks us to multiply two terms involving square roots. Formula: $a\sqrt{b} \times c\sqrt{b} = (a \times c) \times (\sqrt{b} \times \sqrt{b}) = ac \times b$ Step 1: Multiply the coefficients: $7 \times 3 = 21$ Step 2: Multiply the square roots: $\sqrt{11} \times \sqrt{11} = \sqrt{11 \times 11} = \sqrt{121} = 11$ Step 3: Combine: $21 \times 11 = 231$ **Answer:** $231$ 2. **Expand and simplify** $(\sqrt{2} + 2)(\sqrt{2} + 5)$. Use distributive property (FOIL): $(a+b)(c+d) = ac + ad + bc + bd$ Step 1: Multiply each term: $\sqrt{2} \times \sqrt{2} = \sqrt{4} = 2$ $\sqrt{2} \times 5 = 5\sqrt{2}$ $2 \times \sqrt{2} = 2\sqrt{2}$ $2 \times 5 = 10$ Step 2: Add all terms: $2 + 5\sqrt{2} + 2\sqrt{2} + 10$ Step 3: Combine like terms: $5\sqrt{2} + 2\sqrt{2} = 7\sqrt{2}$ $2 + 10 = 12$ **Answer:** $12 + 7\sqrt{2}$ 3. **Rationalise the denominator** $\frac{70}{\sqrt{10}}$. To rationalise, multiply numerator and denominator by $\sqrt{10}$: $$\frac{70}{\sqrt{10}} \times \frac{\sqrt{10}}{\sqrt{10}} = \frac{70\sqrt{10}}{\sqrt{10} \times \sqrt{10}} = \frac{70\sqrt{10}}{10}$$ Step 2: Simplify fraction: $$\frac{70\sqrt{10}}{\cancel{10}} = \frac{\cancel{70}7\sqrt{10}}{\cancel{10}1} = 7\sqrt{10}$$ **Answer:** $7\sqrt{10}$ 4. **Simplify** $10\sqrt{7} + \sqrt{112}$. Step 1: Simplify $\sqrt{112}$. Factor 112: $112 = 16 \times 7$ $$\sqrt{112} = \sqrt{16 \times 7} = \sqrt{16} \times \sqrt{7} = 4\sqrt{7}$$ Step 2: Rewrite expression: $$10\sqrt{7} + 4\sqrt{7}$$ Step 3: Combine like terms: $$10\sqrt{7} + 4\sqrt{7} = (10 + 4)\sqrt{7} = 14\sqrt{7}$$ **Answer:** $14\sqrt{7}$