Subjects algebra

Ratio Problems 924A75

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Use the AI math solver

Question: 11. Simplify the ratio 15:25. 12. In a recipe, the ratio of flour to sugar is 4:1. If 16 cups of flour are used, how many cups of sugar are needed? 13. A man divides 180 between his two sons in the ratio 2:7. How much does the older son receive? 14. 80 is shared among three people in the ratio 1:2:3. How much does the person with the largest share get? 15. If 5 mangoes cost 12.50, how much will 8 mangoes cost?
1. Problem 11: Simplify the ratio $15:25$. The ratio $15:25$ means $\frac{15}{25}$. To simplify, find the greatest common divisor (GCD) of $15$ and $25$, which is $5$. Divide numerator and denominator by $5$: $$\frac{\cancel{15}^3}{\cancel{25}^5} = \frac{3}{5}$$ So, the simplified ratio is $3:5$. 2. Problem 12: Flour to sugar ratio is $4:1$. If flour is $16$ cups, find sugar cups. Let sugar cups be $x$. Set up proportion: $$\frac{4}{1} = \frac{16}{x}$$ Cross multiply: $$4x = 16 \times 1 = 16$$ Divide both sides by $4$: $$x = \frac{16}{4} = 4$$ So, sugar needed is $4$ cups. 3. Problem 13: Divide $180$ in ratio $2:7$ between two sons. Find older son's share. Total parts = $2 + 7 = 9$. Older son's share = $\frac{7}{9} \times 180$. Calculate: $$\frac{7}{9} \times 180 = 7 \times \frac{180}{9} = 7 \times 20 = 140$$ Older son receives $140$. 4. Problem 14: Share $80$ among three people in ratio $1:2:3$. Find largest share. Total parts = $1 + 2 + 3 = 6$. Largest share corresponds to $3$ parts. Calculate: $$\frac{3}{6} \times 80 = \frac{1}{2} \times 80 = 40$$ Largest share is $40$. 5. Problem 15: If $5$ mangoes cost $12.50$, find cost of $8$ mangoes. Cost per mango: $$\frac{12.50}{5} = 2.5$$ Cost for $8$ mangoes: $$8 \times 2.5 = 20$$ So, $8$ mangoes cost $20$. Final answers: 11. $3:5$ 12. $4$ 13. $140$ 14. $40$ 15. $20$