Subjects algebra

Rational Expression B1138A

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Question: Simplify the following rational expression and express in expanded form. $$\frac{k^{10} + 9k^{5} + 18}{k^{10} + 6k^{5} + 9} = \frac{k^{5} + 6}{k^{5} + 3}$$
1. **State the problem:** Simplify the rational expression $$\frac{k^{10} + 9k^{5} + 18}{k^{10} + 6k^{5} + 9}$$ and express it in expanded form. 2. **Rewrite the expression:** We want to simplify $$\frac{k^{10} + 9k^{5} + 18}{k^{10} + 6k^{5} + 9}$$. 3. **Recognize powers:** Notice that $$k^{10} = (k^{5})^{2}$$, so let $$x = k^{5}$$ to simplify the expression. 4. **Rewrite numerator and denominator in terms of $$x$$:** Numerator: $$x^{2} + 9x + 18$$ Denominator: $$x^{2} + 6x + 9$$ 5. **Factor numerator and denominator:** - Numerator: Find factors of 18 that add to 9, which are 6 and 3. $$x^{2} + 9x + 18 = (x + 6)(x + 3)$$ - Denominator: Recognize perfect square trinomial: $$x^{2} + 6x + 9 = (x + 3)^{2}$$ 6. **Rewrite the fraction with factors:** $$\frac{(x + 6)(x + 3)}{(x + 3)^{2}}$$ 7. **Cancel common factors:** $$\frac{\cancel{(x + 3)}(x + 6)}{\cancel{(x + 3)}(x + 3)} = \frac{x + 6}{x + 3}$$ 8. **Substitute back $$x = k^{5}$$:** $$\frac{k^{5} + 6}{k^{5} + 3}$$ 9. **Express in expanded form:** The expression is already simplified and expanded as $$\frac{k^{5} + 6}{k^{5} + 3}$$. **Final answer:** $$\frac{k^{5} + 6}{k^{5} + 3}$$