Question: Solve the rational inequality and graph the solution set on a real number line. Express the solution set in interval notation.
$$\frac{-x + 5}{x - 7} \geq 0$$
1. **State the problem:** Solve the inequality $$\frac{-x + 5}{x - 7} \geq 0$$ and express the solution set in interval notation.
2. **Identify critical points:** The numerator is zero when $$-x + 5 = 0 \Rightarrow x = 5$$.
The denominator is zero when $$x - 7 = 0 \Rightarrow x = 7$$ (excluded from domain).
3. **Determine intervals:** The critical points divide the real line into three intervals:
- $$(-\infty, 5)$$
- $$(5, 7)$$
- $$(7, \infty)$$
4. **Test each interval:**
- For $$x < 5$$, pick $$x = 0$$:
$$\frac{-0 + 5}{0 - 7} = \frac{5}{-7} = -\frac{5}{7} < 0$$ (does not satisfy inequality).
- For $$5 < x < 7$$, pick $$x = 6$$:
$$\frac{-6 + 5}{6 - 7} = \frac{-1}{-1} = 1 > 0$$ (satisfies inequality).
- For $$x > 7$$, pick $$x = 8$$:
$$\frac{-8 + 5}{8 - 7} = \frac{-3}{1} = -3 < 0$$ (does not satisfy inequality).
5. **Check equality at critical points:**
- At $$x = 5$$, numerator zero, denominator nonzero, so $$\frac{0}{5 - 7} = 0$$ satisfies $$\geq 0$$.
- At $$x = 7$$, denominator zero, undefined, exclude from solution.
6. **Write solution set:**
$$[5, 7)$$
**Final answer:** The solution set is $$[5, 7)$$.