Subjects algebra

Rationalise Denominator 31809E

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Question: Rationalise the denominator of $\frac{10 + \sqrt{5}}{4\sqrt{5}}$ Give your answer in its simplest form.
1. **State the problem:** Rationalise the denominator of the expression $$\frac{10 + \sqrt{5}}{4\sqrt{5}}$$ and simplify the result. 2. **Recall the formula and rule:** To rationalise a denominator containing a square root, multiply numerator and denominator by the conjugate or the radical itself to eliminate the root from the denominator. 3. **Multiply numerator and denominator by $\sqrt{5}$:** $$\frac{10 + \sqrt{5}}{4\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = \frac{(10 + \sqrt{5})\sqrt{5}}{4\sqrt{5}\sqrt{5}}$$ 4. **Simplify the denominator:** $$4\sqrt{5}\sqrt{5} = 4 \times 5 = 20$$ 5. **Expand the numerator:** $$ (10 + \sqrt{5})\sqrt{5} = 10\sqrt{5} + (\sqrt{5})^2 = 10\sqrt{5} + 5 $$ 6. **Rewrite the expression:** $$ \frac{10\sqrt{5} + 5}{20} $$ 7. **Factor numerator if possible:** $$ 10\sqrt{5} + 5 = 5(2\sqrt{5} + 1) $$ 8. **Simplify the fraction by canceling common factor 5:** $$ \frac{\cancel{5}(2\sqrt{5} + 1)}{4\cancel{5}} = \frac{2\sqrt{5} + 1}{4} $$ **Final answer:** $$ \boxed{\frac{2\sqrt{5} + 1}{4}} $$