Subjects algebra

Rationalize Denominator 410245

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Question: Express as a fraction in simplest form with a rational denominator: $$\frac{10}{5 - \sqrt{7}}$$
1. **State the problem:** Simplify the expression $$\frac{10}{5 - \sqrt{7}}$$ so that the denominator is rational. 2. **Formula and rule:** To rationalize the denominator when it contains a square root, multiply numerator and denominator by the conjugate of the denominator. The conjugate of $$5 - \sqrt{7}$$ is $$5 + \sqrt{7}$$. 3. **Multiply numerator and denominator by the conjugate:** $$\frac{10}{5 - \sqrt{7}} \times \frac{5 + \sqrt{7}}{5 + \sqrt{7}} = \frac{10(5 + \sqrt{7})}{(5 - \sqrt{7})(5 + \sqrt{7})}$$ 4. **Simplify the denominator using difference of squares:** $$ (5 - \sqrt{7})(5 + \sqrt{7}) = 5^2 - (\sqrt{7})^2 = 25 - 7 = 18 $$ 5. **Write the numerator:** $$ 10(5 + \sqrt{7}) = 50 + 10\sqrt{7} $$ 6. **Put it all together:** $$ \frac{50 + 10\sqrt{7}}{18} $$ 7. **Simplify the fraction by dividing numerator and denominator by 2:** $$ \frac{\cancel{2} \times (25 + 5\sqrt{7})}{\cancel{2} \times 9} = \frac{25 + 5\sqrt{7}}{9} $$ 8. **Final answer:** $$ \boxed{\frac{25 + 5\sqrt{7}}{9}} $$