1. The problem is to find the relation between variables $x$, $y$, and $z$ given the equation $3309x + 6442y = 3z = 13682$. 2. First, note that the equation as written is ambiguous because it uses two equal signs. We interpret it as two separate equalities: $3309x + 6442y = 3z$ and $3z = 13682$. 3. From $3z = 13682$, solve for $z$: $$z = \frac{13682}{3}$$ 4. Substitute $z$ back into the first equation: $$3309x + 6442y = 3 \times \frac{13682}{3} = 13682$$ 5. So the relation between $x$ and $y$ is: $$3309x + 6442y = 13682$$ 6. To express $y$ in terms of $x$, rearrange: $$6442y = 13682 - 3309x$$ $$y = \frac{13682 - 3309x}{6442}$$ 7. Summary: - $z = \frac{13682}{3}$ - $y = \frac{13682 - 3309x}{6442}$ This gives the relation between $x$, $y$, and $z$.