Question: j. 22; -16; -54; -92; ... and then extend it with three more terms.
b. -17; -102; -612; -3 672; ...
1. **Problem Statement:**
We are given two sequences and asked to extend each with three more terms.
2. **Sequence j:** $22, -16, -54, -92, ...$
3. **Step 1: Identify the pattern in sequence j.**
Calculate the differences between consecutive terms:
$$-16 - 22 = -38$$
$$-54 - (-16) = -38$$
$$-92 - (-54) = -38$$
The common difference is $-38$, so this is an arithmetic sequence.
4. **Step 2: Use the arithmetic sequence formula:**
$$a_n = a_1 + (n-1)d$$
where $a_1 = 22$ and $d = -38$.
5. **Step 3: Find the next three terms:**
$$a_5 = 22 + 4 \times (-38) = 22 - 152 = -130$$
$$a_6 = 22 + 5 \times (-38) = 22 - 190 = -168$$
$$a_7 = 22 + 6 \times (-38) = 22 - 228 = -206$$
6. **Sequence j extended:**
$$22, -16, -54, -92, -130, -168, -206$$
7. **Sequence b:** $-17, -102, -612, -3672, ...$
8. **Step 1: Identify the pattern in sequence b.**
Calculate the ratios between consecutive terms:
$$\frac{-102}{-17} = 6$$
$$\frac{-612}{-102} = 6$$
$$\frac{-3672}{-612} = 6$$
The common ratio is $6$, so this is a geometric sequence.
9. **Step 2: Use the geometric sequence formula:**
$$a_n = a_1 \times r^{n-1}$$
where $a_1 = -17$ and $r = 6$.
10. **Step 3: Find the next three terms:**
$$a_5 = -17 \times 6^4 = -17 \times 1296 = -22032$$
$$a_6 = -17 \times 6^5 = -17 \times 7776 = -132192$$
$$a_7 = -17 \times 6^6 = -17 \times 46656 = -792,552$$
11. **Sequence b extended:**
$$-17, -102, -612, -3672, -22032, -132192, -792552$$