Question: 36-40. At what rate of simple interest will ₱7500 earns ₱2050 in 3 years and 4 months? And whats the given?
1. **State the problem:**
We need to find the rate of simple interest that will make ₱7500 earn ₱2050 in 3 years and 4 months.
2. **Given:**
- Principal, $P = 7500$
- Interest, $I = 2050$
- Time, $T = 3$ years and $4$ months = $3 + \frac{4}{12} = 3 + \frac{1}{3} = \frac{10}{3}$ years
3. **Formula for simple interest:**
$$I = P \times R \times T$$
where $R$ is the rate per year (in decimal form).
4. **Rearrange the formula to solve for $R$:**
$$R = \frac{I}{P \times T}$$
5. **Substitute the known values:**
$$R = \frac{2050}{7500 \times \frac{10}{3}}$$
6. **Calculate the denominator:**
$$7500 \times \frac{10}{3} = 7500 \times 3.3333 = 25000$$
7. **Calculate $R$:**
$$R = \frac{2050}{25000} = 0.082$$
8. **Convert $R$ to percentage:**
$$R = 0.082 \times 100 = 8.2\%$$
**Final answer:** The rate of simple interest is $8.2\%$ per year.