Question: User: $\sqrt{25} - 9 + p$ $(-7)^2 - \sqrt{16} =$
1. **State the problem:** Simplify the expression $$\sqrt{25} - 9 + p \quad (-7)^2 - \sqrt{16}$$.
2. **Recall important formulas and rules:**
- The square root of a perfect square $\sqrt{a^2} = a$.
- Squaring a number means multiplying it by itself: $(-7)^2 = (-7) \times (-7)$.
3. **Calculate each term:**
- $\sqrt{25} = 5$ because $5^2 = 25$.
- $(-7)^2 = 49$ because $-7 \times -7 = 49$.
- $\sqrt{16} = 4$ because $4^2 = 16$.
4. **Substitute these values back into the expression:**
$$5 - 9 + p \quad 49 - 4$$
5. **Simplify each part:**
- $5 - 9 = -4$
- $49 - 4 = 45$
6. **Write the simplified expression:**
$$-4 + p \quad 45$$
**Final answer:** $$-4 + p \quad 45$$