Question: The expression 2 (3x² + 7x + 3) − 3 (2x² + 6x + 4) equals
[blank] x² + [blank] x + [blank]
1. **State the problem:** Simplify the expression $$2 (3x^2 + 7x + 3) - 3 (2x^2 + 6x + 4)$$ and write it in the form $$ax^2 + bx + c$$.
2. **Use the distributive property:** Multiply each term inside the parentheses by the factor outside.
$$2 (3x^2 + 7x + 3) = 2 \times 3x^2 + 2 \times 7x + 2 \times 3 = 6x^2 + 14x + 6$$
$$-3 (2x^2 + 6x + 4) = -3 \times 2x^2 - 3 \times 6x - 3 \times 4 = -6x^2 - 18x - 12$$
3. **Combine like terms:**
$$6x^2 + 14x + 6 - 6x^2 - 18x - 12$$
Group the terms:
$$ (6x^2 - 6x^2) + (14x - 18x) + (6 - 12) $$
4. **Simplify each group:**
$$ \cancel{6x^2} - \cancel{6x^2} = 0$$
$$14x - 18x = -4x$$
$$6 - 12 = -6$$
5. **Final simplified expression:**
$$0x^2 - 4x - 6$$
or simply
$$-4x - 6$$
**Answer:** The expression equals $$0x^2 - 4x - 6$$, so the coefficients are:
$$0$$ for $$x^2$$, $$-4$$ for $$x$$, and $$-6$$ for the constant term.