Question: User: 4x^2 - 2y + 7x^2 + 3y - 3x^2 + 5y = (7 - 3)x^2 + (3 - 5)y =
1. **State the problem:** Simplify the expression $$4x^2 - 2y + 7x^2 + 3y - 3x^2 + 5y$$ and verify it equals $$(7 - 3)x^2 + (3 - 5)y$$.
2. **Combine like terms on the left side:**
$$4x^2 + 7x^2 - 3x^2 = (4 + 7 - 3)x^2 = 8x^2$$
$$-2y + 3y + 5y = (-2 + 3 + 5)y = 6y$$
So the left side simplifies to:
$$8x^2 + 6y$$
3. **Simplify the right side:**
$$(7 - 3)x^2 = 4x^2$$
$$(3 - 5)y = -2y$$
So the right side simplifies to:
$$4x^2 - 2y$$
4. **Compare both sides:**
Left side: $$8x^2 + 6y$$
Right side: $$4x^2 - 2y$$
5. **Conclusion:** The two sides are not equal since $$8x^2 + 6y \neq 4x^2 - 2y$$.
**Final answer:** The simplified left side is $$8x^2 + 6y$$, which does not equal the simplified right side $$4x^2 - 2y$$.