Question: User: $(-2k^{-3})^2(6k^2)^4(9k^4)^2$
1. **State the problem:** Simplify the expression $$(-2k^{-3})^2(6k^2)^4(9k^4)^2$$.
2. **Recall the exponent rules:**
- $(ab)^n = a^n b^n$
- $(a^m)^n = a^{mn}$
- When multiplying like bases, add exponents: $a^m \cdot a^n = a^{m+n}$
3. **Apply the power to each term:**
$$(-2k^{-3})^2 = (-2)^2 (k^{-3})^2 = 4 k^{-6}$$
$$ (6k^2)^4 = 6^4 (k^2)^4 = 1296 k^8$$
$$ (9k^4)^2 = 9^2 (k^4)^2 = 81 k^8$$
4. **Multiply all parts together:**
$$4 k^{-6} \times 1296 k^8 \times 81 k^8 = (4 \times 1296 \times 81) k^{-6 + 8 + 8}$$
5. **Calculate the coefficients:**
$$4 \times 1296 = 5184$$
$$5184 \times 81 = 419904$$
6. **Add the exponents of $k$:**
$$-6 + 8 + 8 = 10$$
7. **Final simplified expression:**
$$419904 k^{10}$$