Question: \(= 6x(-3) \times x\)\n\(18x(-2)(-4)\)
1. **Stating the problem:** Simplify the expressions \(6x(-3) \times x\) and \(18x(-2)(-4)\).\n\n2. **Simplify the first expression:** \(6x(-3) \times x\) means multiply \(6x\) by \(-3\) and then by \(x\).\n\n3. Multiply constants and variables separately:\n$$6 \times (-3) = -18$$\n$$x \times x = x^2$$\nSo, \(6x(-3) \times x = -18x^2\).\n\n4. **Simplify the second expression:** \(18x(-2)(-4)\) means multiply \(18x\) by \(-2\) and then by \(-4\).\n\n5. Multiply constants first:\n$$18 \times (-2) = -36$$\n$$-36 \times (-4) = 144$$\nVariables remain as \(x\). So, \(18x(-2)(-4) = 144x\).\n\n**Final answers:**\n- \(6x(-3) \times x = -18x^2\)\n- \(18x(-2)(-4) = 144x\)