Question: Simplify. $\frac{7b^{2}c + 14bc}{7bc}$
1. **State the problem:** Simplify the expression $$\frac{7b^{2}c + 14bc}{7bc}$$.
2. **Write the formula and rules:** To simplify a fraction, factor the numerator and denominator and cancel common factors.
3. **Factor the numerator:** $$7b^{2}c + 14bc = 7bc(b + 2)$$.
4. **Rewrite the expression:** $$\frac{7bc(b + 2)}{7bc}$$.
5. **Cancel common factors:** $$\frac{\cancel{7bc}(b + 2)}{\cancel{7bc}} = b + 2$$.
6. **Final answer:** The simplified expression is $$b + 2$$.