Subjects algebra

Solve Equation 04A74E

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Question: Solve the equation. $\frac{4}{7} (x + 14) = \frac{2}{3} (x - 7)$ Use the keypad to enter your answer in the box. More symbols can be found using the drop-down arrow at the top of the keypad. The solution to the equation is $x = \square$.
1. **State the problem:** Solve the equation $$\frac{4}{7} (x + 14) = \frac{2}{3} (x - 7)$$. 2. **Use the distributive property:** Multiply each fraction by the terms inside the parentheses. $$\frac{4}{7}x + \frac{4}{7} \times 14 = \frac{2}{3}x - \frac{2}{3} \times 7$$ 3. **Calculate the products:** $$\frac{4}{7}x + \frac{56}{7} = \frac{2}{3}x - \frac{14}{3}$$ Simplify the fractions: $$\frac{4}{7}x + 8 = \frac{2}{3}x - \frac{14}{3}$$ 4. **Eliminate fractions by multiplying both sides by the least common denominator (LCD):** The LCD of 7 and 3 is 21. Multiply both sides by 21: $$21 \times \left(\frac{4}{7}x + 8\right) = 21 \times \left(\frac{2}{3}x - \frac{14}{3}\right)$$ 5. **Distribute 21:** $$21 \times \frac{4}{7}x + 21 \times 8 = 21 \times \frac{2}{3}x - 21 \times \frac{14}{3}$$ Simplify each term: $$3 \times 4x + 168 = 7 \times 2x - 7 \times 14$$ $$12x + 168 = 14x - 98$$ 6. **Isolate variable terms on one side and constants on the other:** Subtract $12x$ from both sides: $$\cancel{12x} + 168 = 14x - 12x - 98$$ $$168 = 2x - 98$$ Add 98 to both sides: $$168 + 98 = 2x - 98 + 98$$ $$266 = 2x$$ 7. **Solve for $x$ by dividing both sides by 2:** $$\frac{266}{\cancel{2}} = \frac{2x}{\cancel{2}}$$ $$133 = x$$ **Final answer:** $$x = 133$$