Question: Solve this showing the steps: $5 = a(-2 - \sqrt{5})(-2 + \sqrt{5})$
1. **State the problem:** We need to solve for $a$ in the equation $$5 = a(-2 - \sqrt{5})(-2 + \sqrt{5}).$$
2. **Recall the formula:** The product of conjugates $$(x - y)(x + y) = x^2 - y^2.$$ Here, $x = -2$ and $y = \sqrt{5}$.
3. **Apply the formula:**
$$(-2 - \sqrt{5})(-2 + \sqrt{5}) = (-2)^2 - (\sqrt{5})^2 = 4 - 5 = -1.$$
4. **Substitute back:**
$$5 = a \times (-1)$$
5. **Solve for $a$:**
$$5 = -a$$
6. **Isolate $a$:**
$$a = \cancel{-1} \times \frac{5}{\cancel{-1}} = -5.$$
**Final answer:** $$a = -5.$$