Question: Solve for $b$. Express your answer as a proper or improper fraction in simplest terms.
$$-\frac{5}{8} = -\frac{1}{2} + \frac{3}{4} b$$
1. **State the problem:** Solve for $b$ in the equation $$-\frac{5}{8} = -\frac{1}{2} + \frac{3}{4} b$$.
2. **Isolate the term with $b$:** Add $\frac{1}{2}$ to both sides to move the constant term to the left:
$$-\frac{5}{8} + \frac{1}{2} = \frac{3}{4} b$$
3. **Find a common denominator to add the fractions on the left:**
$$-\frac{5}{8} + \frac{4}{8} = \frac{3}{4} b$$
4. **Simplify the left side:**
$$-\frac{5}{8} + \frac{4}{8} = -\frac{1}{8}$$
So,
$$-\frac{1}{8} = \frac{3}{4} b$$
5. **Solve for $b$ by dividing both sides by $\frac{3}{4}$:**
$$b = \frac{-\frac{1}{8}}{\frac{3}{4}}$$
6. **Rewrite the division as multiplication by the reciprocal:**
$$b = -\frac{1}{8} \times \frac{4}{3}$$
7. **Multiply the numerators and denominators:**
$$b = -\frac{1 \times 4}{8 \times 3} = -\frac{4}{24}$$
8. **Simplify the fraction by dividing numerator and denominator by 4:**
$$b = -\frac{\cancel{4}^1}{\cancel{24}^6} = -\frac{1}{6}$$
**Final answer:**
$$b = -\frac{1}{6}$$