Question: Solve for $c$
$c + 3 + 8 = 12$
$c = [ ]$
1. **State the problem:** Solve for $c$ in the equation $$c + 3 + 8 = 12$$.
2. **Combine like terms:** Add the constants on the left side:
$$c + (3 + 8) = 12$$
$$c + 11 = 12$$
3. **Isolate $c$:** Subtract $11$ from both sides to solve for $c$:
$$c + \cancel{11} - \cancel{11} = 12 - 11$$
$$c = 1$$
4. **Final answer:**
$$c = 1$$