Question: Solve for $v$.
$\frac{v}{3} = \frac{v}{4} - 3$
Simplify your answer as much as possible.
$v = [ ]$
1. **State the problem:** Solve the equation $$\frac{v}{3} = \frac{v}{4} - 3$$ for $v$.
2. **Identify the formula and rules:** This is a linear equation with fractions. To solve, we first eliminate the fractions by finding a common denominator and then isolate $v$.
3. **Eliminate fractions:** The denominators are 3 and 4. The least common denominator (LCD) is 12. Multiply both sides of the equation by 12:
$$12 \times \frac{v}{3} = 12 \times \left(\frac{v}{4} - 3\right)$$
4. **Simplify each term:**
$$12 \times \frac{v}{3} = 4v$$
$$12 \times \frac{v}{4} = 3v$$
$$12 \times (-3) = -36$$
So the equation becomes:
$$4v = 3v - 36$$
5. **Isolate $v$:** Subtract $3v$ from both sides:
$$4v - 3v = 3v - 3v - 36$$
$$\cancel{4v} - \cancel{3v} = -36$$
$$v = -36$$
6. **Final answer:**
$$v = -36$$