Question: Express y as the subject of the formula in the equation $4x = 5 \sqrt[3]{6y - 2p}$
1. **State the problem:** We need to express $y$ as the subject of the formula given the equation $$4x = 5 \sqrt[3]{6y - 2p}$$.
2. **Isolate the cube root term:** Divide both sides by 5 to isolate the cube root.
$$\frac{4x}{5} = \sqrt[3]{6y - 2p}$$
3. **Eliminate the cube root:** Cube both sides to remove the cube root.
$$\left(\frac{4x}{5}\right)^3 = 6y - 2p$$
4. **Expand the cube:**
$$\frac{(4x)^3}{5^3} = 6y - 2p$$
$$\frac{64x^3}{125} = 6y - 2p$$
5. **Isolate $y$:** Add $2p$ to both sides.
$$6y = \frac{64x^3}{125} + 2p$$
6. **Divide both sides by 6:**
$$y = \frac{\frac{64x^3}{125} + 2p}{6}$$
7. **Simplify the expression:**
$$y = \frac{64x^3}{125 \times 6} + \frac{2p}{6}$$
$$y = \frac{64x^3}{750} + \frac{p}{3}$$
**Final answer:**
$$y = \frac{64x^3}{750} + \frac{p}{3}$$