Question: Solve the equation, $k + \frac{6}{9} = -\frac{8}{3}$, for the given variable. Write your final answer as a reduced fraction (not a mixed number).
1. **State the problem:** Solve for $k$ in the equation $$k + \frac{6}{9} = -\frac{8}{3}$$.
2. **Simplify fractions:** Note that $\frac{6}{9}$ can be reduced by dividing numerator and denominator by 3:
$$\frac{6}{9} = \frac{\cancel{3} \times 2}{\cancel{3} \times 3} = \frac{2}{3}$$
3. **Rewrite the equation:**
$$k + \frac{2}{3} = -\frac{8}{3}$$
4. **Isolate $k$:** Subtract $\frac{2}{3}$ from both sides:
$$k = -\frac{8}{3} - \frac{2}{3}$$
5. **Combine the fractions:** Since denominators are the same, subtract numerators:
$$k = \frac{-8 - 2}{3} = \frac{-10}{3}$$
6. **Final answer:** The fraction $\frac{-10}{3}$ is already in lowest terms, so
$$k = -\frac{10}{3}$$