Question: Solve for $x$.
$9x + 9 \leq 27$
$x \leq [?]$
1. **State the problem:** Solve the inequality $$9x + 9 \leq 27$$ for $x$.
2. **Isolate the term with $x$:** Subtract $9$ from both sides to get $$9x + 9 - 9 \leq 27 - 9$$ which simplifies to $$9x \leq 18$$.
3. **Divide both sides by $9$:** Since $9 > 0$, the inequality direction stays the same. $$\frac{\cancel{9}x}{\cancel{9}} \leq \frac{18}{9}$$ which simplifies to $$x \leq 2$$.
4. **Final answer:** $$x \leq 2$$.