Question: User: 5-3x$\le20$
1. **State the problem:** Solve the inequality $$5 - 3x \le 20$$.
2. **Isolate the variable term:** Subtract 5 from both sides:
$$5 - 3x - 5 \le 20 - 5$$
which simplifies to
$$-3x \le 15$$
3. **Divide both sides by -3:** Since we are dividing by a negative number, the inequality sign reverses:
$$\frac{-3x}{\cancel{-3}} \ge \frac{15}{\cancel{-3}}$$
which simplifies to
$$x \ge -5$$
4. **Final answer:** The solution to the inequality is
$$x \ge -5$$.
This means all values of $x$ greater than or equal to $-5$ satisfy the inequality.